Nick and Bobby had a total of 102 coins. Bobby had half as many coins as Nick. How many coins must Nick give to Bobby so they have an equal number of coins?
| |
Nick |
Bobby |
Total |
| Before |
2 u |
1 u |
102 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 102 ÷ 3 = 34
Nick and Bobby have an equal number of coins in the end.
Number of coins that Bobby has in the end
= 102 ÷ 2
= 51
Number of coins that Nick must give to Bobby
= 51 - 34
= 17
Answer(s): 17
