There was an equal number of white and silver balls in a box at first. After 22 silver balls were taken out and 50 white balls were added into the box, there was
17 as many silver balls as white balls. Find the number of silver balls in the box at first.
| |
White balls |
Silver balls |
| Before |
7 u - 50 |
1 u + 22 |
| Change |
+ 50 |
- 22 |
| After |
7 u |
1 u |
The number of white and silver balls in the box is the same at first.
7 u - 50 = 1 u + 22
7 u - 1 u = 22 + 50
6 u = 72
1 u = 72 ÷ 6 = 12
Number of silver balls at first
= 1 u + 22
= 12 + 22
= 34
Answer(s)34
