There was an equal number of red and silver balls in a bag at first. After 12 silver balls were taken out and 44 red balls were added into the bag, there was
15 as many silver balls as red balls. Find the number of silver balls in the bag at first.
|
Red balls |
Silver balls |
Before |
5 u - 44 |
1 u + 12 |
Change |
+ 44 |
- 12 |
After |
5 u |
1 u |
The number of red and silver balls in the bag is the same at first.
5 u - 44 = 1 u + 12
5 u - 1 u = 12 + 44
4 u = 56
1 u = 56 ÷ 4 = 14
Number of silver balls at first
= 1 u + 12
= 14 + 12
= 26
Answer(s)26