There was an equal number of red and green balls in a bag at first. After 30 green balls were taken out and 24 red balls were added into the bag, there was
13 as many green balls as red balls. Find the number of green balls in the bag at first.
|
Red balls |
Green balls |
Before |
3 u - 24 |
1 u + 30 |
Change |
+ 24 |
- 30 |
After |
3 u |
1 u |
The number of red and green balls in the bag is the same at first.
3 u - 24 = 1 u + 30
3 u - 1 u = 30 + 24
2 u = 54
1 u = 54 ÷ 2 = 27
Number of green balls at first
= 1 u + 30
= 27 + 30
= 57
Answer(s)57