Kathy and Opal had a total of $880 at first. After Kathy spent
35 of her money and Opal spent
23 of her money, they had the same amount of money left.
- How much money did Kathy have at first?
- Opal has the same number of $10-notes and $2-notes at first. How many $2-notes did she have at first?
| |
Kathy |
Opal |
Total |
Before |
5 u |
3x2 =
6 u |
11 u |
Change |
- 3 u |
- 2x2 =
- 4 u |
|
After |
2 u |
1x2 =
2 u |
|
(a)
The amount that Kathy and Opal had in the end is the same. Make the amount that they each had in the end the same. LCM of 1 and 2 is 2.
Total amount that Kathy and Opal had at first
= 5 u + 6 u
= 11 u
11 u = 880
1 u = 880 ÷ 11 = 80
Amount that Kathy had at first
= 5 u
= 5 x 80
= $400
(b)
Amount that Opal had at first
= 6 u
= 6 x 80
= $480
Opal has the same number of $10-note and $2-note at first.
Value of 1 set of $10-note and $2-note
= 10 + 2
= $12
Number of 10-notes
= 480 ÷ 12
= 40
Answer(s): (a) $400; (b) 40
