Xylia and Jade had a total of $990 at first. After Xylia spent
13 of her money and Jade spent
34 of her money, they had the same amount of money left.
- How much money did Xylia have at first?
- Jade has the same number of $2-notes and $10-notes at first. How many $10-notes did she have at first?
| |
Xylia |
Jade |
Total |
Before |
3 u |
4x2 =
8 u |
11 u |
Change |
- 1 u |
- 3x2 =
- 6 u |
|
After |
2 u |
1x2 =
2 u |
|
(a)
The amount that Xylia and Jade had in the end is the same. Make the amount that they each had in the end the same. LCM of 1 and 2 is 2.
Total amount that Xylia and Jade had at first
= 3 u + 8 u
= 11 u
11 u = 990
1 u = 990 ÷ 11 = 90
Amount that Xylia had at first
= 3 u
= 3 x 90
= $270
(b)
Amount that Jade had at first
= 8 u
= 8 x 90
= $720
Jade has the same number of $2-note and $10-note at first.
Value of 1 set of $2-note and $10-note
= 2 + 10
= $12
Number of 2-notes
= 720 ÷ 12
= 60
Answer(s): (a) $270; (b) 60
