Joelle and Pamela had a total of $490 at first. After Joelle spent
13 of her money and Pamela spent
12 of her money, they had the same amount of money left.
- How much money did Joelle have at first?
- Pamela has the same number of $2-notes and $5-notes at first. How many $5-notes did she have at first?
| |
Joelle |
Pamela |
Total |
Before |
3 u |
2x2 =
4 u |
7 u |
Change |
- 1 u |
- 1x2 =
- 2 u |
|
After |
2 u |
1x2 =
2 u |
|
(a)
The amount that Joelle and Pamela had in the end is the same. Make the amount that they each had in the end the same. LCM of 1 and 2 is 2.
Total amount that Joelle and Pamela had at first
= 3 u + 4 u
= 7 u
7 u = 490
1 u = 490 ÷ 7 = 70
Amount that Joelle had at first
= 3 u
= 3 x 70
= $210
(b)
Amount that Pamela had at first
= 4 u
= 4 x 70
= $280
Pamela has the same number of $2-note and $5-note at first.
Value of 1 set of $2-note and $5-note
= 2 + 5
= $7
Number of 2-notes
= 280 ÷ 7
= 40
Answer(s): (a) $210; (b) 40
