Henry and Elijah went to buy computers at a sale. The usual price of 1 computer was $900 each.
SALEBuy 1 computer at 20% discount
Buy 2 or more computers at 35% discount each
- Henry bought 1 computer. How much did he pay?
- What is the maximum number of computers Elijah can buy if he has $4000?
(a)
Discounted price of 1 computer in percent if only 1 was bought
= 100% - 20%
= 80%
100% of 1 computer = 900
1% of 1 computer = 900 ÷ 100 = 9
80% of 1 computer = 80 x 9 = 720
Amount that Henry paid for 1 computer = $720
(b)
Discounted price of 1 computer in percent if more than 1 was bought
= 100% - 35%
= 65%
65% of 1 computer = 65 x 9 = 585
Amount that Elijah paid for 1 computer = $585
Maximum number of computers that Elijah can buy if he has $4000
= 4000 ÷ 585
= 6 r 490
Answer(s): (a) $720; (b) 6