Dylan and Ahmad went to buy laptops at a sale. The usual price of 1 laptop was $1400 each.
SALEBuy 1 laptop at 5% discount
Buy 2 or more laptops at 15% discount each
- Dylan bought 1 laptop. How much did he pay?
- What is the maximum number of laptops Ahmad can buy if he has $8000?
(a)
Discounted price of 1 laptop in percent if only 1 was bought
= 100% - 5%
= 95%
100% of 1 laptop = 1400
1% of 1 laptop = 1400 ÷ 100 = 14
95% of 1 laptop = 95 x 14 = 1330
Amount that Dylan paid for 1 laptop = $1330
(b)
Discounted price of 1 laptop in percent if more than 1 was bought
= 100% - 15%
= 85%
85% of 1 laptop = 85 x 14 = 1190
Amount that Ahmad paid for 1 laptop = $1190
Maximum number of laptops that Ahmad can buy if he has $8000
= 8000 ÷ 1190
= 6 r 860
Answer(s): (a) $1330; (b) 6