Jeremy and Ahmad went to buy laptops at a sale. The usual price of 1 laptop was $1800 each.
SALEBuy 1 laptop at 20% discount
Buy 2 or more laptops at 35% discount each
- Jeremy bought 1 laptop. How much did he pay?
- What is the maximum number of laptops Ahmad can buy if he has $7000?
(a)
Discounted price of 1 laptop in percent if only 1 was bought
= 100% - 20%
= 80%
100% of 1 laptop = 1800
1% of 1 laptop = 1800 ÷ 100 = 18
80% of 1 laptop = 80 x 18 = 1440
Amount that Jeremy paid for 1 laptop = $1440
(b)
Discounted price of 1 laptop in percent if more than 1 was bought
= 100% - 35%
= 65%
65% of 1 laptop = 65 x 18 = 1170
Amount that Ahmad paid for 1 laptop = $1170
Maximum number of laptops that Ahmad can buy if he has $7000
= 7000 ÷ 1170
= 5 r 1150
Answer(s): (a) $1440; (b) 5