Fred and Henry went to buy hard drives at a sale. The usual price of 1 hard drive was $800 each.
SALEBuy 1 hard drive at 20% discount
Buy 2 or more hard drives at 35% discount each
- Fred bought 1 hard drive. How much did he pay?
- What is the maximum number of hard drives Henry can buy if he has $6000?
(a)
Discounted price of 1 hard drive in percent if only 1 was bought
= 100% - 20%
= 80%
100% of 1 hard drive = 800
1% of 1 hard drive = 800 ÷ 100 = 8
80% of 1 hard drive = 80 x 8 = 640
Amount that Fred paid for 1 hard drive = $640
(b)
Discounted price of 1 hard drive in percent if more than 1 was bought
= 100% - 35%
= 65%
65% of 1 hard drive = 65 x 8 = 520
Amount that Henry paid for 1 hard drive = $520
Maximum number of hard drives that Henry can buy if he has $6000
= 6000 ÷ 520
= 11 r 280
Answer(s): (a) $640; (b) 11