Ahmad and Howard went to buy laptops at a sale. The usual price of 1 laptop was $600 each.
SALEBuy 1 laptop at 5% discount
Buy 2 or more laptops at 20% discount each
- Ahmad bought 1 laptop. How much did he pay?
- What is the maximum number of laptops Howard can buy if he has $8000?
(a)
Discounted price of 1 laptop in percent if only 1 was bought
= 100% - 5%
= 95%
100% of 1 laptop = 600
1% of 1 laptop = 600 ÷ 100 = 6
95% of 1 laptop = 95 x 6 = 570
Amount that Ahmad paid for 1 laptop = $570
(b)
Discounted price of 1 laptop in percent if more than 1 was bought
= 100% - 20%
= 80%
80% of 1 laptop = 80 x 6 = 480
Amount that Howard paid for 1 laptop = $480
Maximum number of laptops that Howard can buy if he has $8000
= 8000 ÷ 480
= 16 r 320
Answer(s): (a) $570; (b) 16