Warren and Cole went to buy computers at a sale. The usual price of 1 computer was $1300 each.
SALEBuy 1 computer at 10% discount
Buy 2 or more computers at 25% discount each
- Warren bought 1 computer. How much did he pay?
- What is the maximum number of computers Cole can buy if he has $8000?
(a)
Discounted price of 1 computer in percent if only 1 was bought
= 100% - 10%
= 90%
100% of 1 computer = 1300
1% of 1 computer = 1300 ÷ 100 = 13
90% of 1 computer = 90 x 13 = 1170
Amount that Warren paid for 1 computer = $1170
(b)
Discounted price of 1 computer in percent if more than 1 was bought
= 100% - 25%
= 75%
75% of 1 computer = 75 x 13 = 975
Amount that Cole paid for 1 computer = $975
Maximum number of computers that Cole can buy if he has $8000
= 8000 ÷ 975
= 8 r 200
Answer(s): (a) $1170; (b) 8