The number of pears at a shop was 40% more than the number of persimmons. After 80% of the persimmons were sold, there were 72 more pears than persimmons. Find the total number of pears and persimmons at the shop at first.
| |
Pears |
Persimmons |
More |
Total |
| Before |
7 u |
5 u |
|
12 u |
| Change |
|
- 4 u |
|
|
| After |
7 u |
1 u |
6 u |
|
Number of persimmons at first in percent = 100%
Number of pears at first in percent
= 100% + 40%
= 140%
PearsPersimmons =
140100 =
75Number of persimmons sold
= 80% x 5 u
=
80100 x 5 u
= 4 u
Number of more pears than persimmons in the end
= 7 u - 1 u
= 6 u
6 u = 72
1 u = 72 ÷ 6 = 12
Total number of persimmons and pears at first
= 7 u + 5 u
= 12 u
= 12 x 12
= 144
Answer(s): 144
