The number of oranges at a shop was 90% more than the number of chikoos. After 40% of the chikoos were sold, there were 130 more oranges than chikoos. Find the total number of oranges and chikoos at the shop at first.
| |
Oranges |
Chikoos |
More |
Total |
| Before |
19 u |
10 u |
|
29 u |
| Change |
|
- 4 u |
|
|
| After |
19 u |
6 u |
13 u |
|
Number of chikoos at first in percent = 100%
Number of oranges at first in percent
= 100% + 90%
= 190%
OrangesChikoos =
190100 =
1910Number of chikoos sold
= 40% x 10 u
=
40100 x 10 u
= 4 u
Number of more oranges than chikoos in the end
= 19 u - 6 u
= 13 u
13 u = 130
1 u = 130 ÷ 13 = 10
Total number of chikoos and oranges at first
= 19 u + 10 u
= 29 u
= 29 x 10
= 290
Answer(s): 290
