The number of kiwis at a stall was 90% more than the number of persimmons. After 70% of the persimmons were sold, there were 128 more kiwis than persimmons. Find the total number of kiwis and persimmons at the stall at first.
| |
Kiwis |
Persimmons |
More |
Total |
| Before |
19 u |
10 u |
|
29 u |
| Change |
|
- 7 u |
|
|
| After |
19 u |
3 u |
16 u |
|
Number of persimmons at first in percent = 100%
Number of kiwis at first in percent
= 100% + 90%
= 190%
KiwisPersimmons =
190100 =
1910Number of persimmons sold
= 70% x 10 u
=
70100 x 10 u
= 7 u
Number of more kiwis than persimmons in the end
= 19 u - 3 u
= 16 u
16 u = 128
1 u = 128 ÷ 16 = 8
Total number of persimmons and kiwis at first
= 19 u + 10 u
= 29 u
= 29 x 8
= 232
Answer(s): 232
