The number of persimmons at a shop was 60% more than the number of kiwis. After 40% of the kiwis were sold, there were 10 more persimmons than kiwis. Find the total number of persimmons and kiwis at the shop at first.
| |
Persimmons |
Kiwis |
More |
Total |
| Before |
8 u |
5 u |
|
13 u |
| Change |
|
- 2 u |
|
|
| After |
8 u |
3 u |
5 u |
|
Number of kiwis at first in percent = 100%
Number of persimmons at first in percent
= 100% + 60%
= 160%
PersimmonsKiwis =
160100 =
85Number of kiwis sold
= 40% x 5 u
=
40100 x 5 u
= 2 u
Number of more persimmons than kiwis in the end
= 8 u - 3 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Total number of kiwis and persimmons at first
= 8 u + 5 u
= 13 u
= 13 x 2
= 26
Answer(s): 26
