The number of persimmons at a shop was 20% more than the number of oranges. After 80% of the oranges were sold, there were 45 more persimmons than oranges. Find the total number of persimmons and oranges at the shop at first.
| |
Persimmons |
Oranges |
More |
Total |
| Before |
6 u |
5 u |
|
11 u |
| Change |
|
- 4 u |
|
|
| After |
6 u |
1 u |
5 u |
|
Number of oranges at first in percent = 100%
Number of persimmons at first in percent
= 100% + 20%
= 120%
PersimmonsOranges =
120100 =
65Number of oranges sold
= 80% x 5 u
=
80100 x 5 u
= 4 u
Number of more persimmons than oranges in the end
= 6 u - 1 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Total number of oranges and persimmons at first
= 6 u + 5 u
= 11 u
= 11 x 9
= 99
Answer(s): 99
