The number of kiwis at a shop was 40% more than the number of persimmons. After 60% of the persimmons were sold, there were 50 more kiwis than persimmons. Find the total number of kiwis and persimmons at the shop at first.
| |
Kiwis |
Persimmons |
More |
Total |
| Before |
7 u |
5 u |
|
12 u |
| Change |
|
- 3 u |
|
|
| After |
7 u |
2 u |
5 u |
|
Number of persimmons at first in percent = 100%
Number of kiwis at first in percent
= 100% + 40%
= 140%
KiwisPersimmons =
140100 =
75Number of persimmons sold
= 60% x 5 u
=
60100 x 5 u
= 3 u
Number of more kiwis than persimmons in the end
= 7 u - 2 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of persimmons and kiwis at first
= 7 u + 5 u
= 12 u
= 12 x 10
= 120
Answer(s): 120
