The number of persimmons at a store was 90% more than the number of pears. After 80% of the pears were sold, there were 68 more persimmons than pears. Find the total number of persimmons and pears at the store at first.
| |
Persimmons |
Pears |
More |
Total |
| Before |
19 u |
10 u |
|
29 u |
| Change |
|
- 8 u |
|
|
| After |
19 u |
2 u |
17 u |
|
Number of pears at first in percent = 100%
Number of persimmons at first in percent
= 100% + 90%
= 190%
PersimmonsPears =
190100 =
1910Number of pears sold
= 80% x 10 u
=
80100 x 10 u
= 8 u
Number of more persimmons than pears in the end
= 19 u - 2 u
= 17 u
17 u = 68
1 u = 68 ÷ 17 = 4
Total number of pears and persimmons at first
= 19 u + 10 u
= 29 u
= 29 x 4
= 116
Answer(s): 116
