In an envelope, there were a total of 112 notes. 75% of them were $100-notes. The rest were $2-notes. Pierre took out some $100-notes. As a result, the remaining $100-notes made up 30% of the notes left in the envelope. Find the total value of the $100-notes Pierre took out from the envelope.
| |
$100 |
$2 |
Total |
| Before |
3x7 =
21 u |
1x7 =
7 u |
4x7 =
28 u |
| Change |
- ? |
|
|
| After |
3x1 =
3 u |
7x1 =
7 u |
10x1 =
10 u |
75% =
75100 =
34
30% =
30100 =
310
The number of $2-notes remains unchanged. Make the number of $2-notes the same. LCM of 1 and 7 is 7.
Total number of notes at first = 28 u
28 u = 112
1 u = 112 ÷ 28 = 4
Number of $100-notes that Pierre took out from the envelope
= 21 u - 3 u
= 18 u
= 18 x 4
= 72
Total value of $100-notes taken out
= 72 x 100
= $7200
Answer(s): $7200
