In an envelope, there were a total of 40 notes. 60% of them were $50-notes. The rest were $100-notes. Cole took out some $50-notes. As a result, the remaining $50-notes made up 20% of the notes left in the envelope. Find the total value of the $50-notes Cole took out from the envelope.
|
$50 |
$100 |
Total |
Before |
3x2 = 6 u |
2x2 = 4 u |
5x2 = 10 u |
Change |
- ? |
|
|
After |
1x1 = 1 u |
4x1 = 4 u |
5x1 = 5 u |
60% =
60100 =
35
20% =
20100 =
15
The number of $100-notes remains unchanged. Make the number of $100-notes the same. LCM of 2 and 4 is 4.
Total number of notes at first = 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of $50-notes that Cole took out from the envelope
= 6 u - 1 u
= 5 u
= 5 x 4
= 20
Total value of $50-notes taken out
= 20 x 50
= $1000
Answer(s): $1000