In an envelope, there were a total of 45 notes. 40% of them were $50-notes. The rest were $5-notes. Lee took out some $50-notes. As a result, the remaining $50-notes made up 10% of the notes left in the envelope. Find the total value of the $50-notes Lee took out from the envelope.
| |
$50 |
$5 |
Total |
| Before |
2x3 =
6 u |
3x3 =
9 u |
5x3 =
15 u |
| Change |
- ? |
|
|
| After |
1x1 =
1 u |
9x1 =
9 u |
10x1 =
10 u |
40% =
40100 =
25
10% =
10100 =
110
The number of $5-notes remains unchanged. Make the number of $5-notes the same. LCM of 3 and 9 is 9.
Total number of notes at first = 15 u
15 u = 45
1 u = 45 ÷ 15 = 3
Number of $50-notes that Lee took out from the envelope
= 6 u - 1 u
= 5 u
= 5 x 3
= 15
Total value of $50-notes taken out
= 15 x 50
= $750
Answer(s): $750
