Natalie is 20% heavier than Fred. Yen is 50% lighter than Fred. Natalie is 42 kg heavier than Yen. What is Fred's mass?
| Natalie |
Fred |
Yen |
| 120% |
100% |
|
| |
100% |
50% |
| 12 u |
10 u |
5 u |
Natalie's mass compared to Fred's mass in percent
= 100% + 20%
= 120%
Yen's mass compared to Fred's mass in percent
= 100% - 50%
= 50%
120% =
120100 =
121050% =
50100 =
510Fred's mass is the repeated identity. Make Fred's mass the same.
Fred's mass = 10 u
Mass that Natalie has more than Yen
= 12 u - 5 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Fred's mass
= 10 u
= 10 x 6
= 60 kg
Answer(s): 60 kg
