The table shows the heights of David, Lucas, and Joseph. The average height of three children is 164 cm. The digit in the ones place of David's height and the digit in the tens place of Joseph's height are covered by ink blots.
- What is the digit in the ones place of David's height?
- What is the digit in the tens place of Joseph's height?
Total height of the three children
= 3 x 164
= 492 cm
Total height of David and Lucas
= 492 - 146
= 346
346 - 170 - 108
= 68
= 6 tens 8 ones
(a) Digit in the ones place of David's height = 8
(b) Digit in the tens place of Joseph's height = 6
Answer(s): (a) 8; (b) 6