Linda bought some Maths books at $14 each. She also bought an equal number of Chinese books at a different price. The average price of one Maths and one Chinese book was $10. Linda paid $64 more for the Maths books than the Chinese books.
- What was the cost of one Chinese book?
- How many Maths books did Linda buy?
|
Maths |
Chinese |
More |
Number |
1 u |
1 u |
|
Value |
$14 |
$6 |
|
Total value |
14 u |
6 u |
$64 |
(a)
Price of one Chinese book
= 2 x 10 - 14
= 20 - 14
= $6
Amount that Linda paid more for Maths books than Chinese books
= 14 u - 6 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Number of Maths books that Linda bought
= 1 u
= 8
Answer(s): (a) $6; (b) 8