A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.50 |
Every 700 m thereafter or less |
$0.20 |
Lynn paid a taxi fare of $5.50. What was the greatest distance that Lynn could have travelled in the taxi? Give your answer in km.
Amount that Lynn paid for the additional distance
= 5.50 - 3.50
= $2
Number of sets of $0.20 that Lynn paid for the edditional distance
= 2 ÷ 0.20
= 10
Total additional distance that Lynn could have travelled in the taxi
= 10 x 700
= 7000 m
1000 m = 1 km
7000 m = 7000 ÷ 1000 = 7 km
Greatest distance that Lynn could have travelled in the taxi
= 1 + 7
= 8 km
Answer(s): 8 km