A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.60 |
Every 700 m thereafter or less |
$0.50 |
Min paid a taxi fare of $5.60. What was the greatest distance that Min could have travelled in the taxi? Give your answer in km.
Amount that Min paid for the additional distance
= 5.60 - 2.60
= $3
Number of sets of $0.50 that Min paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Min could have travelled in the taxi
= 6 x 700
= 4200 m
1000 m = 1 km
4200 m = 4200 ÷ 1000 = 4.2 km
Greatest distance that Min could have travelled in the taxi
= 1 + 4.2
= 5.2 km
Answer(s): 5.2 km