A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.70 |
Every 300 m thereafter or less |
$0.60 |
Fanny paid a taxi fare of $6.70. What was the greatest distance that Fanny could have travelled in the taxi? Give your answer in km.
Amount that Fanny paid for the additional distance
= 6.70 - 3.70
= $3
Number of sets of $0.60 that Fanny paid for the edditional distance
= 3 ÷ 0.60
= 5
Total additional distance that Fanny could have travelled in the taxi
= 5 x 300
= 1500 m
1000 m = 1 km
1500 m = 1500 ÷ 1000 = 1.5 km
Greatest distance that Fanny could have travelled in the taxi
= 1 + 1.5
= 2.5 km
Answer(s): 2.5 km