A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.90 |
Every 600 m thereafter or less |
$0.20 |
Esther paid a taxi fare of $6.90. What was the greatest distance that Esther could have travelled in the taxi? Give your answer in km.
Amount that Esther paid for the additional distance
= 6.90 - 4.90
= $2
Number of sets of $0.20 that Esther paid for the edditional distance
= 2 ÷ 0.20
= 10
Total additional distance that Esther could have travelled in the taxi
= 10 x 600
= 6000 m
1000 m = 1 km
6000 m = 6000 ÷ 1000 = 6 km
Greatest distance that Esther could have travelled in the taxi
= 1 + 6
= 7 km
Answer(s): 7 km