A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.50 |
Every 700 m thereafter or less |
$0.20 |
Jade paid a taxi fare of $3.50. What was the greatest distance that Jade could have travelled in the taxi? Give your answer in km.
Amount that Jade paid for the additional distance
= 3.50 - 2.50
= $1
Number of sets of $0.20 that Jade paid for the edditional distance
= 1 ÷ 0.20
= 5
Total additional distance that Jade could have travelled in the taxi
= 5 x 700
= 3500 m
1000 m = 1 km
3500 m = 3500 ÷ 1000 = 3.5 km
Greatest distance that Jade could have travelled in the taxi
= 1 + 3.5
= 4.5 km
Answer(s): 4.5 km