A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.20 |
Every 700 m thereafter or less |
$0.50 |
Lynn paid a taxi fare of $8.20. What was the greatest distance that Lynn could have travelled in the taxi? Give your answer in km.
Amount that Lynn paid for the additional distance
= 8.20 - 4.20
= $4
Number of sets of $0.50 that Lynn paid for the edditional distance
= 4 ÷ 0.50
= 8
Total additional distance that Lynn could have travelled in the taxi
= 8 x 700
= 5600 m
1000 m = 1 km
5600 m = 5600 ÷ 1000 = 5.6 km
Greatest distance that Lynn could have travelled in the taxi
= 1 + 5.6
= 6.6 km
Answer(s): 6.6 km