A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.50 |
Every 500 m thereafter or less |
$0.50 |
Rachel paid a taxi fare of $7.50. What was the greatest distance that Rachel could have travelled in the taxi? Give your answer in km.
Amount that Rachel paid for the additional distance
= 7.50 - 4.50
= $3
Number of sets of $0.50 that Rachel paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Rachel could have travelled in the taxi
= 6 x 500
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Rachel could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km