A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.50 |
Every 400 m thereafter or less |
$0.80 |
Shannon paid a taxi fare of $7.50. What was the greatest distance that Shannon could have travelled in the taxi? Give your answer in km.
Amount that Shannon paid for the additional distance
= 7.50 - 3.50
= $4
Number of sets of $0.80 that Shannon paid for the edditional distance
= 4 ÷ 0.80
= 5
Total additional distance that Shannon could have travelled in the taxi
= 5 x 400
= 2000 m
1000 m = 1 km
2000 m = 2000 ÷ 1000 = 2 km
Greatest distance that Shannon could have travelled in the taxi
= 1 + 2
= 3 km
Answer(s): 3 km