A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.40 |
Every 700 m thereafter or less |
$0.80 |
Shannon paid a taxi fare of $6.40. What was the greatest distance that Shannon could have travelled in the taxi? Give your answer in km.
Amount that Shannon paid for the additional distance
= 6.40 - 2.40
= $4
Number of sets of $0.80 that Shannon paid for the edditional distance
= 4 ÷ 0.80
= 5
Total additional distance that Shannon could have travelled in the taxi
= 5 x 700
= 3500 m
1000 m = 1 km
3500 m = 3500 ÷ 1000 = 3.5 km
Greatest distance that Shannon could have travelled in the taxi
= 1 + 3.5
= 4.5 km
Answer(s): 4.5 km