A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.50 |
Every 600 m thereafter or less |
$0.90 |
Usha paid a taxi fare of $11.50. What was the greatest distance that Usha could have travelled in the taxi? Give your answer in km.
Amount that Usha paid for the additional distance
= 11.50 - 2.50
= $9
Number of sets of $0.90 that Usha paid for the edditional distance
= 9 ÷ 0.90
= 10
Total additional distance that Usha could have travelled in the taxi
= 10 x 600
= 6000 m
1000 m = 1 km
6000 m = 6000 ÷ 1000 = 6 km
Greatest distance that Usha could have travelled in the taxi
= 1 + 6
= 7 km
Answer(s): 7 km