A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.20 |
Every 400 m thereafter or less |
$0.60 |
Jade paid a taxi fare of $8.20. What was the greatest distance that Jade could have travelled in the taxi? Give your answer in km.
Amount that Jade paid for the additional distance
= 8.20 - 2.20
= $6
Number of sets of $0.60 that Jade paid for the edditional distance
= 6 ÷ 0.60
= 10
Total additional distance that Jade could have travelled in the taxi
= 10 x 400
= 4000 m
1000 m = 1 km
4000 m = 4000 ÷ 1000 = 4 km
Greatest distance that Jade could have travelled in the taxi
= 1 + 4
= 5 km
Answer(s): 5 km