A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.70 |
Every 300 m thereafter or less |
$0.50 |
Hazel paid a taxi fare of $8.70. What was the greatest distance that Hazel could have travelled in the taxi? Give your answer in km.
Amount that Hazel paid for the additional distance
= 8.70 - 3.70
= $5
Number of sets of $0.50 that Hazel paid for the edditional distance
= 5 ÷ 0.50
= 10
Total additional distance that Hazel could have travelled in the taxi
= 10 x 300
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Hazel could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km