A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.60 |
Every 300 m thereafter or less |
$0.50 |
Lynn paid a taxi fare of $7.60. What was the greatest distance that Lynn could have travelled in the taxi? Give your answer in km.
Amount that Lynn paid for the additional distance
= 7.60 - 2.60
= $5
Number of sets of $0.50 that Lynn paid for the edditional distance
= 5 ÷ 0.50
= 10
Total additional distance that Lynn could have travelled in the taxi
= 10 x 300
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Lynn could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km