A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.70 |
Every 500 m thereafter or less |
$0.60 |
Hazel paid a taxi fare of $9.70. What was the greatest distance that Hazel could have travelled in the taxi? Give your answer in km.
Amount that Hazel paid for the additional distance
= 9.70 - 3.70
= $6
Number of sets of $0.60 that Hazel paid for the edditional distance
= 6 ÷ 0.60
= 10
Total additional distance that Hazel could have travelled in the taxi
= 10 x 500
= 5000 m
1000 m = 1 km
5000 m = 5000 ÷ 1000 = 5 km
Greatest distance that Hazel could have travelled in the taxi
= 1 + 5
= 6 km
Answer(s): 6 km