A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.60 |
Every 300 m thereafter or less |
$0.70 |
Esther paid a taxi fare of $9.60. What was the greatest distance that Esther could have travelled in the taxi? Give your answer in km.
Amount that Esther paid for the additional distance
= 9.60 - 2.60
= $7
Number of sets of $0.70 that Esther paid for the edditional distance
= 7 ÷ 0.70
= 10
Total additional distance that Esther could have travelled in the taxi
= 10 x 300
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Esther could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km