A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.40 |
Every 200 m thereafter or less |
$0.50 |
Gillian paid a taxi fare of $7.40. What was the greatest distance that Gillian could have travelled in the taxi? Give your answer in km.
Amount that Gillian paid for the additional distance
= 7.40 - 4.40
= $3
Number of sets of $0.50 that Gillian paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Gillian could have travelled in the taxi
= 6 x 200
= 1200 m
1000 m = 1 km
1200 m = 1200 ÷ 1000 = 1.2 km
Greatest distance that Gillian could have travelled in the taxi
= 1 + 1.2
= 2.2 km
Answer(s): 2.2 km