A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.20 |
Every 200 m thereafter or less |
$0.50 |
Hilda paid a taxi fare of $7.20. What was the greatest distance that Hilda could have travelled in the taxi? Give your answer in km.
Amount that Hilda paid for the additional distance
= 7.20 - 2.20
= $5
Number of sets of $0.50 that Hilda paid for the edditional distance
= 5 ÷ 0.50
= 10
Total additional distance that Hilda could have travelled in the taxi
= 10 x 200
= 2000 m
1000 m = 1 km
2000 m = 2000 ÷ 1000 = 2 km
Greatest distance that Hilda could have travelled in the taxi
= 1 + 2
= 3 km
Answer(s): 3 km