A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.10 |
Every 300 m thereafter or less |
$0.30 |
Sabrina paid a taxi fare of $5.10. What was the greatest distance that Sabrina could have travelled in the taxi? Give your answer in km.
Amount that Sabrina paid for the additional distance
= 5.10 - 2.10
= $3
Number of sets of $0.30 that Sabrina paid for the edditional distance
= 3 ÷ 0.30
= 10
Total additional distance that Sabrina could have travelled in the taxi
= 10 x 300
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Sabrina could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km