A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.50 |
Every 400 m thereafter or less |
$0.40 |
Mary paid a taxi fare of $5.50. What was the greatest distance that Mary could have travelled in the taxi? Give your answer in km.
Amount that Mary paid for the additional distance
= 5.50 - 3.50
= $2
Number of sets of $0.40 that Mary paid for the edditional distance
= 2 ÷ 0.40
= 5
Total additional distance that Mary could have travelled in the taxi
= 5 x 400
= 2000 m
1000 m = 1 km
2000 m = 2000 ÷ 1000 = 2 km
Greatest distance that Mary could have travelled in the taxi
= 1 + 2
= 3 km
Answer(s): 3 km