A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.20 |
Every 200 m thereafter or less |
$0.20 |
Yoko paid a taxi fare of $6.20. What was the greatest distance that Yoko could have travelled in the taxi? Give your answer in km.
Amount that Yoko paid for the additional distance
= 6.20 - 4.20
= $2
Number of sets of $0.20 that Yoko paid for the edditional distance
= 2 ÷ 0.20
= 10
Total additional distance that Yoko could have travelled in the taxi
= 10 x 200
= 2000 m
1000 m = 1 km
2000 m = 2000 ÷ 1000 = 2 km
Greatest distance that Yoko could have travelled in the taxi
= 1 + 2
= 3 km
Answer(s): 3 km