A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.10 |
Every 600 m thereafter or less |
$0.60 |
Hazel paid a taxi fare of $7.10. What was the greatest distance that Hazel could have travelled in the taxi? Give your answer in km.
Amount that Hazel paid for the additional distance
= 7.10 - 4.10
= $3
Number of sets of $0.60 that Hazel paid for the edditional distance
= 3 ÷ 0.60
= 5
Total additional distance that Hazel could have travelled in the taxi
= 5 x 600
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Hazel could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km