A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.90 |
Every 400 m thereafter or less |
$0.50 |
Xylia paid a taxi fare of $6.90. What was the greatest distance that Xylia could have travelled in the taxi? Give your answer in km.
Amount that Xylia paid for the additional distance
= 6.90 - 2.90
= $4
Number of sets of $0.50 that Xylia paid for the edditional distance
= 4 ÷ 0.50
= 8
Total additional distance that Xylia could have travelled in the taxi
= 8 x 400
= 3200 m
1000 m = 1 km
3200 m = 3200 ÷ 1000 = 3.2 km
Greatest distance that Xylia could have travelled in the taxi
= 1 + 3.2
= 4.2 km
Answer(s): 4.2 km