A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.30 |
Every 800 m thereafter or less |
$0.50 |
Mary paid a taxi fare of $4.30. What was the greatest distance that Mary could have travelled in the taxi? Give your answer in km.
Amount that Mary paid for the additional distance
= 4.30 - 2.30
= $2
Number of sets of $0.50 that Mary paid for the edditional distance
= 2 ÷ 0.50
= 4
Total additional distance that Mary could have travelled in the taxi
= 4 x 800
= 3200 m
1000 m = 1 km
3200 m = 3200 ÷ 1000 = 3.2 km
Greatest distance that Mary could have travelled in the taxi
= 1 + 3.2
= 4.2 km
Answer(s): 4.2 km