A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.10 |
Every 600 m thereafter or less |
$0.50 |
Opal paid a taxi fare of $4.10. What was the greatest distance that Opal could have travelled in the taxi? Give your answer in km.
Amount that Opal paid for the additional distance
= 4.10 - 2.10
= $2
Number of sets of $0.50 that Opal paid for the edditional distance
= 2 ÷ 0.50
= 4
Total additional distance that Opal could have travelled in the taxi
= 4 x 600
= 2400 m
1000 m = 1 km
2400 m = 2400 ÷ 1000 = 2.4 km
Greatest distance that Opal could have travelled in the taxi
= 1 + 2.4
= 3.4 km
Answer(s): 3.4 km